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X^2+0.01X-5000=0
a = 1; b = 0.01; c = -5000;
Δ = b2-4ac
Δ = 0.012-4·1·(-5000)
Δ = 20000.0001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.01)-\sqrt{20000.0001}}{2*1}=\frac{-0.01-\sqrt{20000.0001}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.01)+\sqrt{20000.0001}}{2*1}=\frac{-0.01+\sqrt{20000.0001}}{2} $
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